Re: Oops! Comma operator is the hardest to understand in the C++ standard!
Lighter wrote:
On Jun 22, 6:15 am, jg <jgu...@gmail.com> wrote:
On Jun 21, 10:19 am, Lighter <cqu...@gmail.com> wrote:
On Jun 22, 1:03 am, Markus Schoder <a3vr6dsg-use...@yahoo.de> wrote:
Since one couldn't check whether the conversion happens or not, WHY
did the C++ standard explicitly provide such a rule which doesn't
exist in the C language standard? What confused me is just the
question.
You sure can check if your C++ compiler does the lvalue-to-rvalue
conversion. Try the following code, if it crashes, it does not;
otherwise, it does.
JG
-----------------------
#include <iostream>
int main()
{
int *pi=0;
int x = (*pi, 10);
std::cout << x << std::endl;
return 0;
}- Hide quoted text -
- Show quoted text -
I tried with VS 2005. It didn't crash. That means the compiler doesn't
perform lvalue-to-rvalue conversion.
No, it doesn't mean squat. Undefined behaviour is just that, undefined.
If the compiler [by not following the Standard] actually performs the
conversion, there is no way to tell by observing the undefined behaviour
of the program above.
V
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