Re: What does "-1.#J" mean?

From:
"Victor Bazarov" <v.Abazarov@comAcast.net>
Newsgroups:
comp.lang.c++
Date:
Thu, 1 May 2008 15:51:45 -0400
Message-ID:
<fvd70h$flk$1@news.datemas.de>
Lightmage wrote:

On May 1, 1:42 pm, "Victor Bazarov" <v.Abaza...@comAcast.net> wrote:

Lightmage wrote:

I am using C++ to convert a certain file into an XML file. During
the conversion the program does some arithmetic operations on the
information that is then outputted in xml format. The information
is a double variable.

Usually the output is exactly what it should be, but every so often
the output is "-1.#J".

"-1.#I" (thats an i) means the value is infinite right?
So does anyone know what "-1.#J" means?

Is there some site that has all different types of obscure outputs?

As soon as I know what the "J" means I will know what to look for in
my code and should be able to fix it.


Unfortunately those things are not specified in either C++ or C.
You need to turn to your compiler documentation. See what out of
range numerical outputs they provide. I have not heard of -1.#J
but I've seen something like #INF or some such.

V
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Thank you for your reply V.

I am using Microsoft Visual Studio .NET 2002.
If you happen to know where I should look or have a link that would be
most helpful.
Thank you for narrowing my search!

~Lightmage


I would probably start in http://msdn2.microsoft.com ... And next
time if your question is MSVC-specific, try

    news:microsoft.public.vc.language

Lots of good info there.

V
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