Re: function doesn't return simply skip the return line

From:
Victor Bazarov <v.Abazarov@comAcast.net>
Newsgroups:
comp.lang.c++
Date:
Mon, 21 Jul 2008 10:57:02 -0400
Message-ID:
<g6283u$bts$1@news.datemas.de>
hirsh.dan@gmail.com wrote:

Hello to all, i have the following functions:

string File::readLine(){
    char ch;
    string str;
    ch = read();
    while(ch != LF && ch != CR && ch != -1){
        str.append(1,ch);
        ch = read();
    }
    if(ch == -1){
        cout << "this line could not be read" << endl;
        exit(1);
    }
    //take care of situation where the loop exited with LF but
    //on a system that has CR.
    int tmp = file->tellg();
    if(read() != CR){ //if no CR available on system, return the get
pointer to it's correct location.
        file->seekg(tmp);
    }
    return str;
}

the function is executed correctly but in the end it skips the "return
str" line,
and tun flies with an error.
debugging took me to a qt class moc_myclass.cpp (it's a qt project in
eclipse)
to a line where it says "_id -= 1;"
inside a function called "int myclass::qt_metacall(...)"

can anyone help me??????????


Since 'qt' is not part of C++, you should consider asking in the
newsgroup (or a web forum) dedicated to that. Apparently the code you
posted cannot be verified without the rest of the stuff (which you did
not post).

V
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