Re: How to invoke a member function pointer?
Maximus wrote:
I need to store a member function pointer as a class member, code
below:
struct Struct_Type
{
typedef int (Struct_Type::*FuncType)(int, int);
FuncType funcA;
int func1(int a, int b) { return a+b+c;}
int func2(int a, int b) { return a-b+c; }
int func3(int a, int b) { return a*b+c; }
int c;
};
//Struct_Type value1 = {0, 1 };
Struct_Type value2;
//FuncType funcA = &Struct_Type::func2;
Struct_Type value = {NULL, 10 };
Struct_Type value3 = {&Struct_Type::func3, 100 };
However, when I invoked the member, the compiler (VS 2005) gave me an
error:
std::cout << (value3.*funcA)(20, 10);
error C2065: 'funcA' : undeclared identifier
Well, 'funcA' is unknown without an object. If you intended to use
the same 'funcA' that's defined in 'value3', then it ought to be
std::cout << (value3.*(value3.funcA))(20,10);
V
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