Re: Overloading member functions, some virtual, some not

From:

"Alexander Grigoriev" <alegr@earthlink.net>

Newsgroups:

microsoft.public.vc.language

Date:

Sun, 14 Feb 2010 09:11:30 -0800

Message-ID:

<OJmZBjZrKHA.1800@TK2MSFTNGP02.phx.gbl>

THis is "name hiding" because of overload lookup rules.

You can deal with that by adding:

using RootFinder::findRoot;

in the derived class declaration.

"Dave" <thedaverudolf@gmail.com> wrote in message
news:19dfed9f-182c-4cc3-9bde-4a29905ce9e0@b36g2000pri.googlegroups.com...

Hi folks,

Got the following class hierarchy, and am getting a strange compile
error from it:

class RootFinder
{
public:
virtual ~RootFinder(){}

double findRoot( const Function1D& func, double guess ) const;
virtual double findRoot( const Function1D& func, double min, double
max ) const = 0;

private:
bool findGoodInterval( const Function1D& func, double guess, double&
min, double& max ) const;
};

class BisectionRootFinder : public RootFinder
{
public:
BisectionRootFinder(){}
virtual double findRoot( const Function1D& func, double min, double
max ) const;
};

If I then try to use the second class like so:

   BisectionRootFinder rootFinder;
   const double root = rootFinder.findRoot( func, guess );

I get the following compile error on that second line :

   error C2660: 'BisectionRootFinder::findRoot' : function does not
take 2 arguments

I'm not sure why this is happening, as it should be able to find the
non-virtual version of findRoot(...) that is in the base class. I can
coax it to find it by doing the following:

   BisectionRootFinder bisectRootFinder;
   RootFinder& rootFinder = bisectRootFinder;
   const double root = rootFinder.findRoot( func, guess );

and all works fine. But, why do I need to go through that extra step?
Am I declaring something wrong, or is VC just misbehaving? If it
matters, I am using Visual Studio 2008 Express (version 9.0.30729.1
SP)

Thanks.