Re: Specialization of member functions without inheritance

From:

"Ivan Novick" <ivan.d.novick@gmail.com>

Newsgroups:

comp.lang.c++.moderated

Date:

Thu, 15 Feb 2007 02:48:02 CST

Message-ID:

<1171517760.089208.77340@q2g2000cwa.googlegroups.com>

On Feb 14, 7:19 pm, "Allan Douglas" <allandoug...@gmail.com> wrote:

Hello,

I'm trying to make a method (myfunc) that returns a value if a
template
parameter is non-void, or just don't return a value if the parameter
is void.

-- snip--

But I don't like this solution because I just need to specialize the
function, not the entire class. And I don't want to use inheritance.

-- snip --

There is a way to specialize only the member function? The FAQ doesn't
talk so much about class and function members specialization.

Yes, but IIRC you can not partialy specialize a member function. Only
class templates can be partially specialized.

Here is a sample code for member function specialization

template<typename T>
struct Foo
{
  T myfunc()
  {
    T x = 0;
    return x;
  }
};

template<>
void Foo<void>::myfunc()
{
  std::cout << "Hello World" << std::endl;
}

int main(int argc, char** argv)
{
  Foo<int> f;
  Foo<void> v;

  std::cout << f.myfunc() << std::endl;
  v.myfunc();

  return 0;
}

Ivan Novick
http://www.0x4849.net

--
      [ See http://www.gotw.ca/resources/clcm.htm for info about ]
      [ comp.lang.c++.moderated. First time posters: Do this! ]