Re: a C++ question about union

From:
Andre Kostur <nntpspam@kostur.net>
Newsgroups:
comp.lang.c++
Date:
Mon, 23 Apr 2007 20:02:16 +0000 (UTC)
Message-ID:
<Xns991B850DF4871nntpspamkosutrnet@209.135.99.21>
JDT <jdt_young@yahoo.com> wrote in news:_x7Xh.7473$H_5.4975
@newssvr23.news.prodigy.net:

NM_UPDOWN

With UDN_DELTAPOS notification handler, MS passes a pointer to NMHDR
which yo can cast to NM_UPDOWN*. With NMHDR (shown below) , you can

use

"iDelta" to know the amount it spins while with NMHDR you can use

"code"

to know the event type. What I don't understand is why the same

storage

(the overlap of the last int and unsigned int) can provide two

different

values by casting. Is it not union, is it? This is a C++ (or even a

C)

question. If I underhand it, I may exploit the same tech for my own.
Your advise is appreciated. JD

typedef struct _NM_UPDOWN
{
     NMHDR hdr;
     int iPos;
     int iDelta;
} NMUPDOWN, *LPNMUPDOWN;

typedef struct tagNMHDR
{
     HWND hwndFrom;
     UINT_PTR idFrom;
     UINT code; // NM_ code
} NMHDR;


This is more of a C question than C++, but here goes:

Note that the first member of _NM_UPDOWN is an NMHDR.

So what MS is doing behind the scenes is something like:

{
  _NM_UPDOWN notification;

  notification.hdr.code = NM_WhateverCode;

  CallNotificationFunction(reinterpret_cast<NMHDR *>(&notification);
}

Basically it's relying on the fact that the first part of the NM_UPDOWN
struct actually is a NMHDR object. It's kinda trying to implement
inheritance in the C world.

So when MS is passing you a pointer to NMHDR, it's really passing you a
pointer to the hdr member of an NM_UPDOWN struct. Keep in mind that the
pointer to the first member of a struct is the same as a pointer to the
struct itself.

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