Re: I don't get it

From:
Jo <jo.langie@telenet.be>
Newsgroups:
comp.lang.c++
Date:
Mon, 18 Jun 2007 20:43:36 GMT
Message-ID:
<Y7Cdi.21959$VR7.1386559@phobos.telenet-ops.be>
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Thomas J. Gritzan wrote:

Jo wrote:
 

Imho, if class C is derived from A and B, then C IS an A and a B at the
same time, conceptually.

But i'm understanding that there is a technical implementation problem
here.
   


In the OP you tried to get a B* from a void*. A void pointer is everything
and nothing, the compiler cannot know what type of object it points to.


OK, understood.

So avoid void*. Avoid c-style cast, too. With C++ style cast, the compiler
can warn you whats wrong using them.


OK, will take this into account.

I thought the compiler could figure that out, but i'm clearly over
estimating the compiler and/or C++.

Anyway, it's off topic to go deeper in this. Although that would be a
nice discussion.
   


When it's a language thing, it is on-topic.


The point was: When C is derived from A and B, then C is an A and C is a
B at the same time.

I would have been surprised if C++/the compiler would not be able to do
the up/down casts in this family, even when multiple inheritance is into
play.

(i immediately thought of a system how this would be no problem)

For a moment, i thought John said that C is not a B. But i
misunderstood. Now i understand he said that the void* p is not pointing
to the B object (in the given example) which is right because it's a void*.

If the C++ compiler can figure out the A/B/C up/down casts, then of
course i keep on being a happy C++ -er.

I know all this is pure essential.
I'm a bit amazed/ashamed that i ran into this problem (i.e. using the
void*).
I didn't know that when using a void*, you explicitly abandon all type
info, except for the source type.

Perhaps you are expecting an ordinary cast to work like a
dynamic_cast? When you write

bp2=(B*)p; // resulting bp2 is WRONG!

you are expecting the program to 'discover' that there a B object
hidden inside the object that p is pointing to?

If so google for dynamic_cast, or better still read a good book.
     


I understand that a dynamic_cast cannot do a base-to-derived conversion,
so that's not the solution here.
   


dynamic_cast can, and is exactly the right tool, to do base-to-derived
conversion. It's like static_cast with an explicit runtime type check.


I understand.

So i'm still looking for the solution for this situation

class A {

public:
virtual long GetClassID() { return(' A'); }
};
   


[...]
 

class C : public class A, public class B {

public:
virtual long GetClassID() { return(' C'); }
};

foo1(C *cp) {
...
foo2(cp);
...
}

foo2(A *ap) {

if (ap->GetClassID==' C') {
  C *cp=(C*)ap; // IS THIS LEGAL and PORTABLE C++ ?
}
}
   


When you know that an A* points to a C object, you can static_cast it to a
C*. But why inventing your own RTTI? You can use typeid and dynamic_cast
instead.


It's indeed about having a 'little private' RTTI system.

I would like to not use RTTI because i heard about the overhead it brings.

Not sure if that is memory or cpu overhead, or both?

The application i'm working on is a multi-threaded realtime application
where part of the code runs at interrupt level.

And that code must be fast, and may not do any dynamic memory allocs!

So that's why i want to play it safe.

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Thomas J. Gritzan wrote:<br>
<blockquote type="cite" cite="midf56p8k$1ss$1@newsreader3.netcologne.de">
  <pre wrap="">Jo wrote:
  </pre>
  <blockquote type="cite">
    <pre wrap="">Imho, if class C is derived from A and B, then C IS an A and a B at the
same time, conceptually.

But i'm understanding that there is a technical implementation problem
here.
    </pre>
  </blockquote>
  <pre wrap=""><!---->
In the OP you tried to get a B* from a void*. A void pointer is everything
and nothing, the compiler cannot know what type of object it points to.</pre>
</blockquote>
<br>
<tt>OK, understood.<br>
<br>
</tt>
<blockquote type="cite" cite="midf56p8k$1ss$1@newsreader3.netcologne.de">
  <pre wrap="">So avoid void*. Avoid c-style cast, too. With C++ style cast, the compiler
can warn you whats wrong using them.</pre>
</blockquote>
<tt><br>
OK, will take this into account.<br>
<br>
</tt>
<blockquote type="cite" cite="midf56p8k$1ss$1@newsreader3.netcologne.de">
  <blockquote type="cite">
    <pre wrap="">I thought the compiler could figure that out, but i'm clearly over
estimating the compiler and/or C++.

Anyway, it's off topic to go deeper in this. Although that would be a
nice discussion.
    </pre>
  </blockquote>
  <pre wrap=""><!---->
When it's a language thing, it is on-topic.</pre>
</blockquote>
<br>
<tt>The point was: When C is derived from A and B, then C is an A and C
is a B at the same time.<br>
<br>
I would have been surprised if C++/the compiler would not be able to do
the up/down casts in this family, even when multiple inheritance is
into play.<br>
<br>
(i immediately thought of a system how this would be no problem)<br>
<br>
For a moment, i thought John said that C is not a B. But i
misunderstood. Now i understand he said that the void* p is not
pointing to the B object (in the given example) which is right because
it's a void*.<br>
<br>
If the C++ compiler can figure out the A/B/C up/down casts, then of
course i keep on being a happy C++ -er.<br>
<br>
I know all this is pure essential.<br>
I'm a bit amazed/ashamed that i ran into this problem (i.e. using the
void*).<br>
I didn't know that when using a void*, you explicitly abandon all type
info, except for the source type.<br>
<br>
</tt>
<blockquote type="cite" cite="midf56p8k$1ss$1@newsreader3.netcologne.de">
  <blockquote type="cite">
    <blockquote type="cite">
      <pre wrap="">Perhaps you are expecting an ordinary cast to work like a
dynamic_cast? When you write

bp2=(B*)p; // resulting bp2 is WRONG!

you are expecting the program to 'discover' that there a B object
hidden inside the object that p is pointing to?

If so google for dynamic_cast, or better still read a good book.
      </pre>
    </blockquote>
    <pre wrap="">
I understand that a dynamic_cast cannot do a base-to-derived conversion,
so that's not the solution here.
    </pre>
  </blockquote>
  <pre wrap=""><!---->
dynamic_cast can, and is exactly the right tool, to do base-to-derived
conversion. It's like static_cast with an explicit runtime type check.</pre>
</blockquote>
<tt><br>
I understand.<br>
<br>
</tt>
<blockquote type="cite" cite="midf56p8k$1ss$1@newsreader3.netcologne.de">
  <blockquote type="cite">
    <pre wrap="">So i'm still looking for the solution for this situation

class A {

 public:
 virtual long GetClassID() { return(' A'); }
};
    </pre>
  </blockquote>
  <pre wrap=""><!---->[...]
  </pre>
  <blockquote type="cite">
    <pre wrap="">class C : public class A, public class B {

 public:
 virtual long GetClassID() { return(' C'); }
};

foo1(C *cp) {
 ...
 foo2(cp);
 ...
}

foo2(A *ap) {

 if (ap-&gt;GetClassID==' C') {
   C *cp=(C*)ap; // IS THIS LEGAL and PORTABLE C++ ?
 }
}
    </pre>
  </blockquote>
  <pre wrap=""><!---->
When you know that an A* points to a C object, you can static_cast it to a
C*. But why inventing your own RTTI? You can use typeid and dynamic_cast
instead.</pre>
</blockquote>
<br>
<tt>It's indeed about having a 'little private' RTTI system.<br>
<br>
I would like to not use RTTI because i heard about the overhead it
brings.<br>
<br>
Not sure if that is memory or cpu overhead, or both?<br>
</tt><tt><br>
The application i'm working on is a multi-threaded realtime application
where part of the code runs at interrupt level.<br>
<br>
And that code must be fast, and may not do any dynamic memory allocs!<br>
<br>
So that's why i want to play it safe.<br>
</tt>
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