Re: How to program this in C++?

From:
 Pavel Shved <Pavel.Shved@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Thu, 08 Nov 2007 09:44:25 -0000
Message-ID:
<1194515065.849532.57090@i13g2000prf.googlegroups.com>
On Nov 8, 11:58, Kai-Uwe Bux <jkherci...@gmx.net> wrote:

Pavel Shved wrote:

On 8 , 10:24, Kai-Uwe Bux <jkherci...@gmx.net> wrote:

a) public inheritance. That would expose the integer part of your float
to independent manipulation (essentially like making the integer data
member public, BadIdea(tm)). On top of that, you get into all sorts of
trouble with pointers to integer objects that now could point to floats,
and more importantly, your float type would match any function

  integer some_function ( integer const & )

which you probably don't want.


I think matching floats in integer funtions is the thing one likely
does want. That's done not by inheritance (which won't work in the
way you expect floats to act as integers), but by specifying user-
defined typecast rather.


I am not sure that I want floats to silently match integer functions. Have a
look at the return type. For a simple function like

  integer sqr ( integer const & i ) {
    return ( i*i );
  }

the result could be rather surprising when you feed in a float. Life will
get even more surprising if you also provide a conversion constructor
interger -> float. Then, you could do:

  float a = ...
  a = sqr( a );

and what you get is not exactly what you see.


I see the following: float variable is passed to an integer function
and i expect the same behaviour as with intrinsic C++ types. And i do
get it. Of course if you don't like this endeavour you may fix it
out, but i prefer writing intgrality-indepentent functions with
templates, like

template <typename T> T sqr (T const& _t)
{
  return _t*_t;
}

, letting integers calculated with aid of floating algorithms fit to
greates-common-divisor functions or something with no explicit
conversions.

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