Re: Is this "upcast" legal?
On Apr 26, 4:43 pm, Peter Simons <sim...@cryp.to> wrote:
Hi,
the following code snippet compiles fine and behaves as expected,
but I wonder whether that behavior is guaranteed by the standard:
It is.
Simplified example follows:
#include <iostream>
struct base
{
};
struct derived : public base
{
void print() { std::cout << "derived::print()" << std::endl; }
};
int main(int, char**)
{
derived d;
base& b = d;
static_cast<derived &>(i._base).print();
return 0;
}
Why does that static_cast from `base' to `derived' succeed?
Does the simplified example help answer the question?
If not, the answer is that it works because the object referered to by
the reference to base is actually of type derived.
Would this code still work in case multiple inheritance?
It would, unless base was a virtual base class of derived (in which
case the code would fail to compile - but could be fixed by using
dynamic_cast)
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