Re: dynamic binding issue

Hi,

obviously, I'm missing something w.r.t. dynamic binding in C++:

Can anyone explain why the code below prints "Base" instead of
"Derived" when calling the Base constructor? I'm calling f() on
a Derived instance in the Base constructor, right? So why isn't
the f() of Derived called as it is in main()?

Can I work around this to get the behaviour that I expected?

Thanks,

#include <iostream>
#include <typeinfo>
class Base {
  public:
    Base(Base *x) {
        x->f(); // why base??
    }
    virtual void f(void) {
        std::cout << "Base\n";
    }
};
class Derived:public Base {
  public:
    Derived():
      Base(this) {
    }
    void f(void) {
        std::cout << "Derived\n";
    }
};
int main(void) {
    Derived derived;
    Base &base = derived;
    base.f(); // ok, derived
}