Re: Why can't call a base member function from a object of sub class???

From:
Albright <zhutongliang@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Mon, 16 Feb 2009 18:52:45 -0800 (PST)
Message-ID:
<e7242516-9d99-4807-bf39-7a35f35a351f@r15g2000prh.googlegroups.com>
On Feb 17, 10:37 am, "Alf P. Steinbach" <al...@start.no> wrote:

* Albright:

Code as bellow:

#include <stdio.h>
#include <string.h>

class A
{
public:
   void print(char *s)
   {
           printf("%s\n", s);
   }
};

class B : public A
{
public:
   void print(int i)
   {
           printf("%d\n", i);
   }
};

int main()
{
   B b;
   b.print("hello"); //Has complile error here, it indicates that b
invoke B::print() but not A::print, I want to know why.

   return 0;
}

In this sample, if print(char *s) is defined in class B, it's OK, bu=

t

if in A, it's not.
Why these two functions are NOT overloaded between base class and sub
class?


This is a FAQ (Frequently Asked Question).

See the FAQ item titled "What's the meaning of, Warning: Derived::f(char)=

 hides

Base::f(double)?", currently item 23.9 and available at e.g. <url:http://=

www.parashift.com/c++-faq-lite/strange-inheritance.html#faq-23.9>, plus

at a host of mirror sites.

It's often a good idea to check the FAQ.

Cheers & hth.,

- Alf


Thanks.

But Why the C++ standard has this rule?

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