Re: Storing const references to other objects in another object.

From:
"Leigh Johnston" <leigh@i42.co.uk>
Newsgroups:
comp.lang.c++
Date:
Wed, 7 Apr 2010 15:52:03 +0100
Message-ID:
<-Z6dnTJPhuaEASHWnZ2dnUVZ8jGdnZ2d@giganews.com>
"Leigh Johnston" <leigh@i42.co.uk> wrote in message
news:NbKdnaUiK4GPEyHWnZ2dnUVZ7tmdnZ2d@giganews.com...

"Kai-Uwe Bux" <jkherciueh@gmx.net> wrote in message
news:hpi1pp$9jv$1@news.doubleSlash.org...

Leigh Johnston wrote:

"Leigh Johnston" <leigh@i42.co.uk> wrote in message
news:GcqdnSD3UOs4HiHWnZ2dnUVZ8j2dnZ2d@giganews.com...

"Daniel T." <daniel_t@earthlink.net> wrote in message
news:daniel_t-548CC7.08435507042010@70-3-168-216.pools.spcsdns.net...

James Allsopp <jamesaallsopp@googlemail.com> wrote:

I have a list of item objects which I'm trying to find which of these
objects are close to each other. The data in these objects does not
change. I const::iterate though the vector these are stored in, and
where the condition is met, create a linker object in another class.
I
don't want to recreate the classes, just store a reference to them.
The code from the linker is

class linker{
public:
        linker( const item &spectra, const item & core, double
distance):spectra(spectra),core(core),distance(distance){};
        const item & spectra;
        const item & core;
        double distance;
        int toString() const;

};


References were designed for argument passing, and it isn't
appropriate
to use them as member-variables. Hold your items in const pointers
instead.


Not true, references were designed to be an alias to another object not
just for argument passing. It is perfectly fine to have reference
member
variables but if the class needs to be Assignable (to be compatible
with
a container for example) then reference member variables may not be
suitable. Your generalization is simply wrong though.

/Leigh


It is possible to re-seat a member reference in a user provided
assignment
operator by doing something similar to the following:

const foo& foo::operator=( const foo& other)
{
  if ( this != &other )
  {
    this->~foo(); // lifetime of *this ends
    new (this) foo(other); // new object of type foo created
  }
  return *this;
}


Yes, it is possible. However, there are some traps with that idea of
which
one should be aware. E.g., that assignment operator does not really
interact
nicely with inheritance in OO design (virtual members and such). E.g.:

#include <iostream>

struct X {

 X ( void ) {
   std::cout << "creating X\n";
 }

 virtual
 ~ X ( void ) {
   std::cout << "destroying X\n";
 }

 X & operator= ( X const & other ) {
   if ( this != &other ) {
     // this->~X();
     this->X::~X();
     new (this) X (other);
   }
   return ( *this );
 }

};

struct Y : public X {

 Y ( void ) {
   std::cout << "creating Y\n";
 }

 ~ Y ( void ) {
   std::cout << "destroying Y\n";
 }

 Y & operator= ( Y const & other ) {
   X::operator=( other );
   return (*this );
 }

};

int main ( void ) {
 Y* a_ptr = new Y;
 Y* b_ptr = new Y;
 *a_ptr = *b_ptr;
 delete a_ptr;
 std::cout << "-----------\n";
 Y* c_ptr = new Y;
 delete c_ptr;
}

This has formally undefined behavior [3.8/7] and on my machine prints:

creating X
creating Y
creating X
creating Y
destroying X
destroying X
-----------
creating X
creating Y
destroying Y
destroying X

Best

Kai-Uwe Bux


Perhaps you can reply to my (couple of months old) post in comp.std.c++
that this caveat (and the other of possibly erroneously calling a dtor)
should be added to the example in 3.8/7 of the draft (n3035)? Two voices
are better than one.

/Leigh


Sorry after re-reading the draft your caveat is already present. Excuse my
inability to read posts fully.

/Leigh

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