Re: sizeof most-derived-class

From:
tonydee <tony_in_da_uk@yahoo.co.uk>
Newsgroups:
comp.lang.c++
Date:
Wed, 7 Apr 2010 20:22:41 -0700 (PDT)
Message-ID:
<c800f09d-e13a-4a43-80fe-5c7ef68db22e@q23g2000yqd.googlegroups.com>
On Apr 8, 11:54 am, Joshua Maurice <joshuamaur...@gmail.com> wrote:

On Apr 7, 7:25 pm, tonydee <tony_in_da...@yahoo.co.uk> wrote:

On Apr 8, 3:04 am, munna <saggitarius.a...@gmail.com> wrote:

Considering the classic diamond problem in where we have this
relationship,
                                  =

                 A

                                  =

               / \

                                  =

             B C

                                  =

              \ /

                                  =

                 D

 and define our classes like the following:

class A{
public:
     virtual void f1(){}};

class B: public virtual A{
public:
     void f1(){}};

class C: public virtual A{
public:
      void f1(){}};

class D: public B, public C{
public:
      void f1(){}

};

 Specifically how the memory-layout for class D-object would be lai=

d

out (in practice). Or is it so that since the standard doesn't
mandates any specific layout, compilers are free to have it at their
discretion? What i understand is that size of class A would be 4 byte=

s

(on a 32-bit architecture), sizeof B and C would be 8 bytes (one vptr
for B/C and one pointer to virtual base class A). How exactly would a
D object look like?


As Victor says, this isn't specified in the Standard, but typically a
compiler will want D to be a concatenation of a B and C object, as it
needs to be able to pass a pointer-to-(some-part-of)-D to functions
accepting B* or C*, and such functions aren't going to want to perform
some run-time check to see if parts of the B or C object are laid out
in a different layout used by some derived classes. So, expect sizeo=

f

D to be sizeof B + sizeof C.


Virtual inheritance is involved. I would specifically expect not that.
For MSVC 2008 on a 32 bit build, I happened to get
sizeof A == 4
sizeof B == 8
sizeof C == 8
sizeof D == 12


For SunC++ 5.8 and g++ 3.4.3 I get 4, 4, 4 and 8.

WHAT FOLLOWS IS NOT PORTABLE. DO NOT RELY ON IT IN PRODUCTION CODE.

All D objects need to contain a B subobject, a C subobject, and
exactly one A subobject. As such, it cannot simply put A's members at
offset 0 in the B subobject and offset 0 in the C suboject. (Think
about it.)


Agreed, but B and C may both embed a pointer to the single A.

For virtual inheritance, the offset to a base class
subobject is no longer a compile time constant, and it must be looked
up at runtime, hence this extra "stuff" in the B, C, and D objects.


True... via the pointer.

Cheers,
Tony

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