Re: Pure virtual functions: declaring a function in a base class

From:
Martin <rio_de_janeiro_2002@hotmail.com>
Newsgroups:
comp.lang.c++
Date:
Wed, 25 Aug 2010 10:16:22 -0700 (PDT)
Message-ID:
<0e13e430-1610-4cca-89ba-d03629888f76@v6g2000prd.googlegroups.com>
Hey Alf,
     Thanks for the reply.
     I don't see why I should declare a function "virtual" to override
a virtual function, I noly need to declare it virtual in the base
class, not in the derived class, but maybe I misunderstood what you
said.
     That being said, I still don't understand why the compiler won't
take B's func1 as an override for class A. I understand your proposals
and agree with them, but I would like to understand why the compiler
won't override func1(). Maybe I just need to go back and read about c+
+ compiler implementation...

     You understood the problem perfectly, I'll go and read the FAQ
about posting...

Thanks,
     Mart=EDn.

On Aug 25, 12:35 am, "Alf P. Steinbach /Usenet" <alf.p.steinbach
+use...@gmail.com> wrote:

* Martin, on 25.08.2010 05:11:

Why doesn't this work? Is there a way to achieve it?
Compiler complains about func1() not being defined in class C, which
inherits it from class B.

class A
{
public:
   virtual void func1() = 0;
}

class B
{
   public func1()
   {
           printf("test");
   }

};

class C : public B, public A
{

};

int _tmain(int argc, _TCHAR* argv[])
{
   C c;
   c.func1();
   return 0;
}


Presumably you want the implementation in B to override the one in A.

And although you're not posting your real code, the typing mistakes that =

you've

made seem to indicate that you come from a Java background. Which is help=

ful in

helping you. But in general, don't assume that your readers are telepaths=

 and

can see what's only in your head or on your screen: that's just stupid. P=

ost

*real code*. See the FAQ about how to ask about Code That Does Not Work.

Now, B::func1 is not virtual, so it can't override anything.

However, if you make B::func1 virtual then you still don't get an overrid=

e, only

a call ambiguity. The compiler sees 2 possibilities for which function yo=

u're

trying to call. And nothing decides between them.

You can either

   * add an override in class C, e.g. calling the B::func1, or

   * make A an abstract class, which means change the inheritance so =

that C

     inherits B inherits A (in this case func1 becomes virtual in B=

 since it's

     already virtual in A, and B::func1 becomes an override of A::f=

unc1), or

   * make A a logical interface, which means let B inherit virtually =

from A and

     let C inherit virtually from A, and in this case B implements =

the A

     interface A for class C, at some run time and design level cos=

t.

That said, there is no such thing as '_tmain' in C++. It's a Microsoft
monstrosity, and moreover it's a monstrosity (only) in support of Windows=

 9x,

which one may presume that you're not out to support? Use a standard 'mai=

n'.

You don't use the 'main' arguments so no point in declaring them.

Finally you can omit the 'return 0', since 'main' returns 0 by default.

Cheers & hth.,

- Alf

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