Re: duct typing and interface in C++

From:
Nobody <nobody@nowhere.com>
Newsgroups:
comp.lang.c++
Date:
Sun, 24 Jul 2011 21:21:56 +0100
Message-ID:
<pan.2011.07.24.20.21.55.211000@nowhere.com>
On Sun, 24 Jul 2011 20:23:59 +0200, TP wrote:

In fact, I would like to have duck typing exactly as in Python:


Then use Python.

in Python
there is no need to have an inheritance relation between the interface and
the class Daffy.


That's because Python is a dynamically-typed language, where method
look-up is done at run time.

In my previous post, I pointed to an example with no such inheritance
relation:

http://stackoverflow.com/questions/289176/how-is-duck-typing-different-from-
the-old-variant-type-and-or-interfaces


Note that the code given there isn't valid C++.

I would like to have a construction where the following affectation is
possible:

InterfaceDuck * d = new Daffy;

without inheritance relation between InterfaceDuck and Daffy.
The fact that Daffy has a method Quack() as InterfaceDuck should be enough
to allow that.

But perhaps there is no means to do that in C++?


Well, not unless you consider using C++ to write a dynamically-typed
language such as Python to be a solution.

If, for some reason, you can't make specific classes derive from
InterfaceDuck, you can use a template to create a wrapper or proxy for
such classes, e.g.:

template <class T>
class ProxyDuck : public InterfaceDuck {
    T& ref;
    ProxyDuck(T& ref) : ref(ref) {}
    void quack() { ref.quack(); }
};

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