Re: Accessibility of inherited injected-class-names
On Mar 26, 4:36 am, Nikolay Ivchenkov <ts...@mail.ru> wrote:
Consider the following example:
template <class T>
struct A {};
struct B : private A<void> {};
struct C : B
{
A<void> a; // A is the injected-class-name of A<void>
};
int main() {}
As far as I understand, in the declaration of C::a identifier A
denotes the injected-class-name of A<void> (i.e. ::A<void>::A) which
is inaccessible within C (thus, the program is ill-formed and a
diagnostic message is required). Is my understanding correct?
The behavior of compilers differs:
1) GNU C++ 4.8.0, Clang 3.0, and VC++ 10.0 do not issue any error or
warning.
2) Intel C++ 12.1 issues the following diagnostic message:
(8): error #308: type "A<T>::A [with T=void]" (declared at line 2)
is inaccessible
A<void> a;
^
{trailing banner removed - mod/we}
In my perception, it shouldn't throw any compilation error.
Becuase in class C, A<T> class is instantiated for T = void, which is
in global namespace.
For this instantiation inheritance will not play any role.
Daya
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