Re: Multiple Inheritance ambiguity but not really?
On Apr 11, 2:16 am, Nick Overdijk <n...@dotsimplicity.net> wrote:
blargg wrote:
Nick Overdijk wrote:
[...]
So if we'd have a class base and c, we can create a diamond
inheritance:
class base;
class a : base;
class b : base;
class c : a, b;
Their memory-pictures are like this:
base: [base]
a: [base][a]
b: [base][b]
c: [base][a][base][b][c]
c, more specific, looks like this: [a::base][a][b::base][b][c]
So, naturally, a::base and b::base data members can differ,
but a::base::func() must be the same as b::base::func()
given that a and b don't overload and func() is not virtual
right? How else can they be different?
[the question was why then is the non-static call
c.base::func() ambiguous]
It's ambiguous because a c has two base sub-objects, and you
haven't specified which one you want to invoke base::func()
on. The fact that for either one the same member function
would be invoked isn't relevant; it's the 'this' pointer
that is.
Hm, yeah. I understand. Is there a way (besides virtual
inheritance) to have a class that resembles this:
[base][a][b][c] ?
I'm not sure I understand the question. What it seems to boil
down to is: is there any way, except the existing way(s), to
have a class [...]. This is what virtual inheritance was
designed for.
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