Re: Conversion operators and private inheritance

From:
=?ISO-8859-1?Q?Daniel_Kr=FCgler?= <daniel.kruegler@googlemail.com>
Newsgroups:
comp.lang.c++.moderated
Date:
Mon, 1 Feb 2010 07:57:57 CST
Message-ID:
<2fe171e2-501b-4bd1-8727-bc53c0a7616f@c29g2000yqd.googlegroups.com>
On 1 Feb., 06:34, Konstantin <k...@gmx.com> wrote:

Hello,
I`ve run into situation when conversion operator to the parent class
provided by the child class (private inheritance is used) is not found by
compiler. Consider the following example :

class A {};
class B : public A {};
class C : private B {
public:
    // By default, "A" base class is not available for the
    // outside non-friend classes and functions. Make it accessible
    // for others
    operator A& () {return *this;}};

void doSomething (const A&) {}

int main (int argc, char** argv){
    C instC;
    // Attempt 1, most obvious. causes compiler error
    doSomething (instC.operator A&());
    // Attempt 2. Causes compiler error
    doSomething (instC);
    // Attempt 3. Fine
    doSomething (instC.C::operator A&());
    return 0;

}

Compiler output (gcc 4.4.1) :

gcc_private_inheritance.cpp: In function ?int main(int, char**)?:
gcc_private_inheritance.cpp:2: error: ?class A? is inaccessible
gcc_private_inheritance.cpp:13: error: within this context
gcc_private_inheritance.cpp:15: error: ?A? is an inaccessible base of ?C

Let`s don`t discuss the sanity of this inheritance scheme / need for
conversion operator :)

So can anyone explain why conversion operator is not found in (1) and (2) ?


See [class.conv.fct]/1:

"A conversion function is never used to convert a (possibly
cv-qualified) object to the (possibly cv-qualified) same object
type (or a reference to it), to a (possibly cv-qualified) base
class of that type (or a reference to it), or to (possibly
cv-qualified) void.[Foot note 111]

111) These conversions are considered as standard
conversions for the purposes of overload resolution
(13.3.3.1, 13.3.3.1.4) and therefore initialization (8.5)
and explicit casts (5.2.9). A conversion to void does
not invoke any conversion function (5.2.9). Even
though never directly called to perform a conversion,
such conversion functions can be declared and can
potentially be reached through a call to a virtual
conversion function in a base class."

HTH & Greetings from Bremen,

Daniel Kr?gler

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