Re: Checking for null pointer for structure

From:
"Alf P. Steinbach" <alfps@start.no>
Newsgroups:
comp.lang.c++
Date:
Wed, 17 Feb 2010 14:31:33 +0100
Message-ID:
<hlgr7i$tce$1@news.eternal-september.org>
* Nick Keighley:

On 17 Feb, 11:06, "Alf P. Steinbach" <al...@start.no> wrote:

* GrzybSon:

Hello,
I have got two nested structures:
struct TopStruct
{
    char * ggg;
    union
    {
        NestedStruct nested;
    } param;
};
struct NestedStruct
{
    InnerStruct inner;
};
struct InnerStruct
{
    char * txt;
}
How to check if field nested of type NestedStruct is not null?
Some code given:
TopStruct * top;
while ( (top = GetStructs()) != NULL)
{
    // ...
    if (top->nested != NULL) // this gives me compiler error c2678 binary
'!=' : no operator found which takes a left hand operand of type
    {
            // do something
    }
}
What is wrong?

The design. Sorry, that's brutal, and even though I'm pretty old I've not yet
learned how to say such things in some acceptable way. So I just go for the
straightforward, hoping people will forgive me since the info is good, yes?

Okay, others will probably comment on your char*'s, recommending instead
std::string, but let's look at the design.

As I understand it you want TopStruct to have an optional NestedStruct.

Some TopStruct-s will have a NestedStruct, some will not.

The question is, will any given TopStruct ever /acquire/ or /lose/ a
NestedStruct, or is a TopStruct created with/without a NestedStruct and staying
that way for its lifetime?

If it stays that way for its lifetime, then a natural solution is to use
inheritance.

It then goes like this:

   struct TopStruct
   {
       virtual ~TopStruct() {} // You need /some/ virtual method.
       std::string ggg;
   };

   struct WithNestedStruct: TopStruct // Inheritance
   {
       std::string text;
   };

   ...

   while( (top = GetStructs()) != 0 )
   {
       if( WithNestedStruct* p = dynamic_cast<WithNestedStruct*>( top ) )
       {
           // Do things with p
       }
   }

There are more advanced techniques to avoid the 'if' or 'case', that is, to
avoid explicit type discrimantion, and generally those techniques are based on
using virtual methods. In short, you let the effect of a call to method depend
on the object at hand. But perhaps first try if you can get the above to work,
assuming of course that the assumption of TopStruct-s staying the way they're
created, holds.

If that assumption does not hold, then use a pointer in TopStruct, and then take
care not to copy those structs, or if you do, decide on what to do with pointer.


looks rather heavy machinary for a simple job...
inheritance for a simple optional sub-field?


Even for a simple optional sub-field it's less to write both for definitions and
usage, and it's more safe, than an embedded pointer.

So it's not exactly heavy machinery; at the source code level it's rather the
opposite, the simplest solution, if the assumptions on which it's based hold.

And on top of that, that even for the simplest case it's simplest, I think one
can be sure that the OP's case is not a simple optional sub-field, and also that
the OP will benefit from learning some OO techniques, using C++ as C++ instead
of as C -- much of the point of C++ is that it has safe & simple direct
language support for many of the patterns that are re-implemented time and time
again in C, so, let the language do its job...

but then we don't know why this nested structure is sometimes here
sometimes not.


Cheers,

- Alf

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