Re: Resolution of ambiguous members in multiple inheritance
On 2012-02-22 17:11, Thomas Richter wrote:
If a class inheriting is a member of a same name from two distinct
bases, as in the following example:
struct A {
int a;
A()
: a(1)
{ }
};
struct B {
int a;
B()
: a(1)
{ }
};
struct C : public A,B {
int getA()
{
return a;
}
};
int main(int argc,char **argv)
{
struct C c;
return c.getA();
}
the compiler clearly refuses the code on the basis that C::a could be
either A::a or B::a. Somehow, I had the expectation that inserting a
struct C : public A,B {
using A::a; // <---
int getA()
{
return a;
}
};
should resolve this ambiguity, as it expresses what I would prefer to
do, but apparently, this is not the case.
Adding the using-declaration should resolve the ambiguity. Which compiler did you test? (I'm not aware of any recent compiler that does not handle this situation properly).
HTH & Greetings from Bremen,
Daniel Kr?gler
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