Re: [Newbie] Namespace and inheritance...

From:
Victor Bazarov <v.bazarov@comcast.invalid>
Newsgroups:
comp.lang.c++
Date:
Fri, 13 Jul 2012 17:06:33 -0400
Message-ID:
<jtq2kp$mom$1@dont-email.me>
On 7/13/2012 4:54 PM, plug.gulp@gmail.com wrote:

Hello,

I am learning C++. I wrote the following C++ code to understand
namespace and inheritance. It does not compile(g++ 4.6.3), but when I
explicitly specify the scope resolution the program works. Why am I not
able to directly call the public method implemented in the base class?

namespace N1 {
     class C
     {
         public:
             void F(const std::string& s)
             {
                 std::cout << "N1::C::F(str): " << s.c_str() << std::endl;
             }
     };
};

namespace N2 {
     class C : public N1::C
     {
         public:
             void F(int i)
             {
                 std::cout << "N2::C::F(int): " << i << std::endl;
             }
     };
};

int main()
{
     N2::C c;
     c.F(1);

     // The following statement does not compile unless
     // it is called with full scope resolution as follows:
     // c.N1::C::F("one");

     c.F("one");

     return 0;
}


This is covered by the FAQ. Please read FAQ before posting. You can
find the FAQ Lite here: http://www.parashift.com/c++-faq-lite/. Hint:
see section 23. And crank up the warning level on your compiler, maybe
you will get a useful diagnostic out of that tool for a change...

V
--
I do not respond to top-posted replies, please don't ask

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