Re: [Newbie] Namespace and inheritance...

From:
Bo Persson <bop@gmb.dk>
Newsgroups:
comp.lang.c++
Date:
Sat, 14 Jul 2012 13:55:29 +0200
Message-ID:
<a6d51gFkdrU2@mid.individual.net>
Bo Persson skrev 2012-07-14 13:51:

plug.gulp@gmail.com skrev 2012-07-13 22:54:

Hello,

I am learning C++. I wrote the following C++ code to understand
namespace and inheritance. It does not compile(g++ 4.6.3), but when I
explicitly specify the scope resolution the program works. Why am I
not able to directly call the public method implemented in the base
class?

namespace N1 {
     class C
     {
         public:
             void F(const std::string& s)
             {
                 std::cout << "N1::C::F(str): " << s.c_str() <<
std::endl;
             }
     };
};

namespace N2 {
     class C : public N1::C
     {
         public:
             void F(int i)
             {
                 std::cout << "N2::C::F(int): " << i << std::endl;
             }
     };
};

int main()
{
     N2::C c;
     c.F(1);

     // The following statement does not compile unless
     // it is called with full scope resolution as follows:
     // c.N1::C::F("one");

     c.F("one");

     return 0;
}


It has nothing to do with namespaces.

Declaring something named F in the derived class hides the name F from
any base classes. This is similar to declaring local variables in an
inner scope which hides names from outer scopes.

If you want to use the name anyway, you can either use the full name
(like you did), or add a "using N1::C::F;" to class C2.


                                                 ^^^^^^^^
Here "class C2" of course should be "class C in namespace N2".

Bo Persson

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