Re: Can anyone explain this, bug in GCC????

From:
"Alf P. Steinbach" <alfps@start.no>
Newsgroups:
comp.lang.c++
Date:
Mon, 09 Feb 2009 20:22:37 +0100
Message-ID:
<gmpvm4$e1k$1@news.motzarella.org>
* Joost Kraaijeveld:

Hi,

Can anyone try to explain why on the line marked with "----->" the
variable "start" changes from it's original value to another value,
being const?

Example output (GCC 4.2 and 4.3 on Linux, 4.3 on Windows):

start 0: H
start 3: H
start 4: H
start 5a: A
start 5b: H

If you want the full source code:
http://trac.askesis.nl/svn/tidbits/AIAStar/Main.cpp

line 577 and further

1 file, can be compiled by gcc 4.2 /4.3 Windows/Linux with an installed
boost library

void findAStarCheapestPath( const Vertex& start,
                const Vertex& finish,
                Vertices pathVertices,
  Edges pathEdges,
  Vertices& allDiscoveredVertices,
  Vertices& cheapestPathVertices,
  Edges& cheapestPathEdges) const
 {
  Vertex localStart = start;
  std::cout << "start 0: " << start << "\n";

  pathVertices.insert( pathVertices.end(), /*start*/localStart);

  Edges vertexEdges = getEdgesFor( /*start*/localStart);
  Edges::iterator e = vertexEdges.begin();
  while (e != vertexEdges.end())
  {
  const Vertex& nextVertex = (*e).otherSide( /*start*/localStart);
  //std::cout << "start 1: " << /*start*/localStart << "\n";
  if (nextVertex == finish )
  {
  pathEdges.insert( pathEdges.end(), (*e));
  pathVertices.insert( pathVertices.end(), finish);
  std::cout << "start 2: " << start << "\n";
  break;
  }
  std::cout << "start 3: " << start << "\n";
  if (std::find( allDiscoveredVertices.begin(),
allDiscoveredVertices.end(), nextVertex) == allDiscoveredVertices.end()
  &&
  std::find( pathVertices.begin(), pathVertices.end(), nextVertex) ==
pathVertices.end())
  {
  std::cout << "start 4: " << start << "\n";
  allDiscoveredVertices.insert(allDiscoveredVertices.begin(), nextVertex);
------------------> std::cout << "start 5a: " << start << "\n";
  std::cout << "start 5b: " << /*start*/localStart << "\n";
  }


'const' is only a promise that the routine won't change the object.

Have you considered aliasing.

Other than that, try to reduce the problem to a minimum, complete program and
post it.

Cheers & hth.,

- Alf

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