Re: How to initialise member variable in template construction

From:
Angus <anguscomber@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Wed, 1 Sep 2010 14:55:46 -0700 (PDT)
Message-ID:
<e4a0dc4b-7f64-4a66-a214-d813510bd8c1@f42g2000yqn.googlegroups.com>
On 1 Sep, 22:51, "Francesco S. Carta" <entul...@gmail.com> wrote:

Angus <anguscom...@gmail.com>, on 01/09/2010 14:43:29, wrote:

I am trying to set the strategy (algorithm) used in a context by
template. Here is my context class (which is incorrectly
implemented):
template<class TStrategy>
class Context //TStrategy is the algorithm
{
     private:
         TStrategy * strategy_; //knows about StrategyInte=

rface

     public:
         void execute() const
         {
             strategy_->execute();
         }
};

The strategies:
class StrategyInterface
{
     public:
         virtual void execute() const = 0; //abstract class=

 - interface

only
};

//the actual concrete algorithms
class ConcreteStrategyA: public StrategyInterface
{
     public:
         virtual void execute() const
         {
             cout<< "Called ConcreteStrategyA execute =

method"<< endl;

         }
};

And I want to do something like this:
Context<ConcreteStrategyA> contextD;
contextD.execute();

But I need to initialise the context data member properly. how do I
do that?


I'm not sure about "how" you would do that, but I know "where" you
should do that: in a constructor. There is none in the code you posted, w=

hy?

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I guess I just need to add this:
Context(){ strategy_ = new TStrategy; }
~Context() { delete strategy_; }

Could I do it without using the heap?

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