Re: the crtp and static polymorphism

From:
sebastian <sebastiangarth@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Thu, 17 Feb 2011 10:27:46 -0800 (PST)
Message-ID:
<6a82d1cb-a867-4c6c-84f8-1f4403abd469@x4g2000prf.googlegroups.com>
On Feb 17, 10:09 am, AdlerSam <Christof.Warl...@siemens.com> wrote:

Hi,

I try to understand static polymorphism in the context of the
curiously recurring template pattern, but fail desperately to catch
the point.

Please have a look at the following code:

#include <iostream>
using namespace std;
template <class Derived> struct Base {
    void interface() {
        static_cast<Derived*>(this)->implementation();
    }};

struct Derived1 : Base<Derived1> {
    void implementation() {cout << "Derived1 member" << endl;}};

struct Derived2 : Base<Derived2> {
    void implementation() {cout << "Derived2 member" << endl;}};

int main() {
    Base<Derived1> *x;
    x = new Derived1();
    x->interface();
    // I can't assign a Derived2 instance to x!?
    return 0;

}

To me, polymorphism means that it should be possible to assign either
an instance of Derived1 or Derived2 to the _same_ variable (x in the
example), and then, when calling a member fuction through x (i.e.
interface()), having the right implementation being run.

Can anyone help me showing where I'm off the track?


Simple: Base<Derived1> and Base<Derived2> are not derived from a
common base, so they are incompatible.

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