Re: assignment/initialization of container - map

From:
ricecake@gehennom.invalid (Marcus Kwok)
Newsgroups:
comp.lang.c++
Date:
Tue, 18 Jul 2006 19:54:34 +0000 (UTC)
Message-ID:
<e9je9q$5lh$1@news-int.gatech.edu>
Thomas Tutone <Thomas8675309@yahoo.com> wrote:

xuatla wrote:

Another question: how can I print the score of a given student's name?

void getScore(std::map<string, int> myMap, const std::string& stuName)
{
     return myMap.find(stuName)->second();
}

Is this correct? Any better solution?


First, unless you want to DRASTICALLY inefficient, better to pass the
map by reference instead of by value. Second, you can't return a value
if you declare the function void. Finally, although theoretically
slightly less efficient, more clear in my view is to use operator[] and
dump the separate function altogether:

   myMap[stuName]

or if you insist on the separate function, make it:

int getScore(std::map<string, int>& myMap, const std::string& stuName)
{
   return myMap[stuName];
}


However, if stuName is not already in the map, the myMap[stuName]
version will automatically create an entry for it, and
default-initialize(?, maybe it's zero-initialize) it. Using
myMap.find(), this case can be handled separately if desired.

    // untested and uncompiled
    int getScore(const std::map<std::string, int>& myMap,
                 const std::string& stuName)
    {
        std::map<std::string, int>::const_iterator i = myMap.find(stuName);

        if (i != myMap.end()) {
            return i->second;
        }
        else {
            return -1;
        }
    }

I do agree that the myMap[stuName] syntax is easier to read though,
however it cannot be used on a const map (or a reference to a const map)
because of the automatic-entry-creation behavior.

--
Marcus Kwok
Replace 'invalid' with 'net' to reply

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