Re: vector of (int,string). can't convert i->first to int

From:
LR <lruss@superlink.net>
Newsgroups:
comp.lang.c++
Date:
Wed, 15 Aug 2007 08:17:27 -0400
Message-ID:
<46c2ee86$0$22478$cc2e38e6@news.uslec.net>
Milan Krejci wrote:

Probably better not to top post here, someone might complain about it.

hello thanks for the reply.
i have a vector

Minor point, but you mean a map, not a vector, right?

of 15,"something" ... 19,"something"...20,"something
else".. 32,"something"


What do the ellipses represent? Are there other values?
15,"something"
16,"something"
17,"something"
18,"something"
19,"something"
20,"something else"
21,"something else"
and so on up to
31,"something else"
32,"something"

 > and i'm trying to find out from what int to what

int there is "something" in the pair.


Do you really mean "something" or just any value? Could we see:

10,"X"
11,"X"
12,""
13,""
14,"Y"
15,"X"
16,"X"

  in other words i need to get

first==15, latest==19, typ=="something" and
first= , latest==31, typ=="something else".


Given the data you provided, would you also see

 > first==32, latest==32, typ=="something"

QString was a QT toolkit's implementation of a string class.


Why are you using it? I think it just confuses the issue. For one
thing you're using std::string in your map, for another, it's not part
of the C++ standard and at least some of the readers here are unfamiliar
with it.

Jim Langston napsal(a):

"Milan Krejci" <rdw@no-spam.mail.cz> wrote in message


I snipped the OPs code. Jim's is easier to read and edit, which I've done.

Did I say that Jim's code was easier to read because of the nice indenting?

I don't know what you are trying to show. Formatting your code and
replacing QString with std::string and changing it so it compiles, it
compiles.

#include <iostream>
#include <map>
#include <string>


You might want to consider a typedef for this
    typedef std::map<int,std::string> MyMap; // or a better name

I'd think about putting this whole thing in a function. At the very
least it'll make it easier to test.

    void first_last(const MyMap &SeznamPracovniDoby) {

        if(SeznamPracovniDoby.empty())
            return;

    //>> int first=15,latest=15;

How do you know that the first key in the map is 15?

    // being at the start is just like being at the
    // begining of a new 'typ', so initialize
    // typ, first and latest
    std::string typ = SeznamPracovniDoby.begin()->second;
    int first = SeznamPracovniDoby.begin()->first;
    // we're at the start so we initialize latest with first
    // we should always do that when we are at the first entry
    // of a 'typ'
    int latest = first;

    for(MyMap::const_iterator i = SeznamPracovniDoby.begin(); i !=
SeznamPracovniDoby.end(); i++) {

These next two lines aren't needed and raise the question of what
happens if the "something" in the first entry in the map has a value of
"". Or what if any entry in the map has a value of ""?

//>> if ( typ == "" )
//>> typ = i->second.c_str();

        if (typ!=i->second.c_str())
        {
            std::cout<<first<<"-"<<latest<<":"<<typ;

  did you want a '<< std::endl' at the end of that line?

            first=i->first;


There are some problems here. If you trace carefully though the code
and maybe add some trace you'll probably see it.

        }
        else
        {


Some problems here too. Same suggestion.

            latest=i->first;
            typ=i->second.c_str();
        }


Maybe this next line
// std::cout << i->first << " " << i->second << std::endl;
Should be
        std::cout<<first<<"-"<<latest<<":"<<typ << std::endl;
    }

}


void test1() {
    MyMap m;
    // set up some data here and call the function
    first_last(m);
}

put test2() and as many others as you want here...

I snipped this and moved it from above
int main()
{
    test1();
    test2();
    // etc..
}

I don't know what you're trying to do though, and I don't know what
QString actually is. Post some compilable code that demonstrates the
problem.


Good idea.

LR

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