Re: Re: behavior of a std::map I don't understand...

From:
Heck <heckja@inordertostymieharvestersverizon.net>
Newsgroups:
comp.lang.c++
Date:
Sun, 18 Nov 2007 03:19:43 GMT
Message-ID:
<rnbvj3ht6848vmtess819fkhu5pacl9ogk@4ax.com>
jeffrey.j.schmitz@gmail.com!

On Nov 15, 11:41 pm, Erik WikstrFm <Erik-wikst...@telia.com> wrote:

On 2007-11-16 00:12, Heck wrote:

I'm using Visual Studio 2005, but i don't think that's (primarily)
where I've gone wrong.

I was experimenting, trying, by the way, to move into writing my own
iterator so that I can learn, ultimately, to write templates:
std::map< int, char [12]> cm;
char str0[12] = {'f','i','r','s','t',' ','t','e','x','t','\0'};

cm[0] = str0;

The compiler says about that assignment,
left operand must be l-value

What does this mean, what's happened here?

It compiles without error when the value arg in the map is instead a
char or a char *.
std::map< int, char *> cm;


You can not store an array in a map (or any other collection for that
matter).

--
Erik WikstrFm


Wrap your array in a class and define the assignment operator


I'm getting to that, yes. Thanks very much.

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