Re: Initializing a map...

From:
Jeff Schwab <jeff@schwabcenter.com>
Newsgroups:
comp.lang.c++
Date:
Wed, 20 Feb 2008 16:22:31 -0800
Message-ID:
<BqKdnY_9-t6_WSHanZ2dnUVZ_tijnZ2d@comcast.com>
barcaroller wrote:

Is there a way in C++ to initialize an STL map in one statement (the way
arrays can be initialized in C)?

For example, instead of using:

    map<type1,type2> mymap;
    mymap[key1] = value1;
    mymap[key2] = value2;

I would like to use something like:

    // wrong syntax!
    map<type1,type2> mymap = { (key1, value1), (key2, value2) };


There's no special syntax for maps. You do have a few options, though.
  One is to initialize an array with the nicer syntax, then initialize
the map from the array.

     typedef std::map<type1, type2> map_type;
     typedef map_type::value_type pair_type;

     template<typename T, std::size_t z>
     std::size_t size(T const (&a)[z]) {
         return z;
     }

     int main() {
         pair_type initializers[] =
             { pair_type(key1, value1), pair_type(key2, value2) };
         map_type m(initializers, initializers + size(initializers));
     }

Another option is to create the map within a function, then return it by
value.

     map_type create_map() {
         map_type result;
         result.insert(pair_type(key1, value1));
         result.insert(pair_type(key2, value2));
         return result;
     }

     int main() {
         map_type map = create_map();
     }

A third option is to let the map start out empty, then use a function to
populate it.

     void populate(map_type& m) {
         m.insert(pair_type(key1, value1));
         m.insert(pair_type(key2, value2));
     }

     int main() {
         map_type m;
         populate(m);
     }

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