Re: question on map< list<T>::iterator, int>

From:
=?utf-8?Q?David_C=C3=B4me?= <davidcome@wanadoo.fr>
Newsgroups:
comp.lang.c++
Date:
Sat, 03 May 2008 15:06:58 +0200
Message-ID:
<op.uakxdwu4rttu86@debian>
On Sat, 03 May 2008 14:48:01 +0200, subramanian100in@yahoo.com, India =

<subramanian100in@yahoo.com> wrote:

Consider the program x.cpp :

#include <cstdlib>
#include <iostream>
#include <list>
#include <map>

using namespace std;

int main()
{
        map<list<int>::iterator, int> m;

        list<int> c;
        c.push_back(100);

        // m[c.begin()] = 10;

        return EXIT_SUCCESS;
}

This program compiles fine with the command
g++ -std=c++98 -pedantic -Wall -Wextra x.cpp

However if I remove the comment, I get compilation error because
operator '<' is not defined for list<T>::iterator. Why doesn't the
compiler give this error for
'map<list<int>::iterator, int> m;' itself. That is, in this first
statement inside main() itself, the compiler can know that the less-
than operator cannot be defined for the key type. So, why does the
compiler wait for an element to be pushed on to the map to flag the
error ?

Kindly clarify

Thanks
V.Subramanian


A map is alway sorted by <.
To use an objet like a key for a std::map, these objet must have defined=
  =

operator<.

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