Re: Overhead of subscript operator for STL maps

From:
=?UTF-8?B?RXJpayBXaWtzdHLDtm0=?= <Erik-wikstrom@telia.com>
Newsgroups:
comp.lang.c++
Date:
Fri, 17 Oct 2008 15:27:51 GMT
Message-ID:
<X92Kk.3361$U5.20777@newsb.telia.net>
On 2008-10-17 09:43, Stephen Horne wrote:

On Thu, 16 Oct 2008 20:32:13 +1300, Ian Collins <ian-news@hotmail.com>
wrote:

The subscript operator creates a default constructed object then copies
the passed object to it. So you will see a copy for the operator call
and one for the copy in.


Wow!

I always assumed that using [] for a key that isn't already in the
container would throw an exception. It seems like an obvious case of
most-likely-a-mistake to me.

I realise that scripting languages do it, but they get to handle the
[] differently depending on whether its on the left side of an
assignment or not. They still complain if you try to read a
non-existent key.

And even with the [] on the left of an assignment, I still think it's
a bit bad, since to me the obvious intent is to overwrite the data for
an existing key.


Personally I consider it a good idea, it can simplify a lot of code
(such as this one, written by Fred Swartz):

#include <iostream>
#include <map>
#include <string>
using namespace std;

int main() {
    map<string, int> freq; // map of words and their frequencies
    string word; // input buffer for words.

    //--- Read words/tokens from input stream
    while (cin >> word) {
        freq[word]++;
    }

    //--- Write the count and the word.
    map<string, int>::const_iterator iter;
    for (iter=freq.begin(); iter != freq.end(); ++iter) {
        cout << iter->second << " " << iter->first << endl;
    }
    return 0;
}//end main

Notice how little code is dedicated to the actual counting of the words.

--
Erik Wikstr??m

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