Re: g++4.3.2 w/ c++0x: error: no type named ?iterator? in ?class std::unordered_map<...'
Samuel.Hornus@gmail.com wrote:
Hi,
I have a problem with g++ 4.3.2 in -std=c++0x mode.
Here is some code which works fine:
struct My_data
{
typedef std::map<Key, My_data, Compare> My_Map; (***)
typedef typename My_map::iterator My_iterator;
// data members
My_iterator cousin_;
};
typedef std::map<Key, My_data, Compare> My_Map;
My_map Family;
Note, that it uses My_data as the data_value for the std::map type
defined in the My_data struct *itself*.
This works fine. But now I want to change std::map by
std::unordered_map.
So do I, with appropriate hash function and Equality comparator.
But then, g++ 4.3.2 gives me the following error:
error: no type named ?iterator? in ?class std::unordered_map<...'
at line (***). I know this does come from the fact that I'm using
My_data as a template parameter inside the definition of the struct
My_data itself.
But... it did work for std::map... so why shouldn't it work for
unordered_map ?
Is there a workaround ? is this a bug of libstd++ ?
Thank you very much !
sam
It just happened to work for std::map, even though it is not required.
The workaround would possibly be to store a pointer or a reference to
the cousin, instead of an iterator.
Bo Persson
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