Re: templates: find the syntax error!

From:
jaybus56 <busch.juergen@gmx.net>
Newsgroups:
comp.lang.c++
Date:
Mon, 22 Dec 2008 13:52:22 -0800 (PST)
Message-ID:
<e3623642-bd9b-4a01-ac4e-45043b230065@z28g2000prd.googlegroups.com>
On 22 Dez., 14:42, Bertwim <b...@xs4all.nl> wrote:

Hi,

I can't understand the compiler's error message in the following
template definition:

In a header file (.h), I have declared
=========================

==========

template <class T>
class symtblpp
{
private:
    typedef std::map< std::string, T > maptype;
    maptype _map;
public:
    T* lookup( const std::string& );};

=========================

===========

In the implementation file (.cpp), the member 'lookup' is defined:
=========================

=========

template <class T>
T* symtblpp<T>::lookup( const std::string& key )
{
    maptype::iterator it = _map.find( key );
    return &(*it);}

=========================

========

The error message is (++, 4.3.1)

symtblpp.cpp:42: error: expected `;' before =91it'
symtblpp.cpp:45: error: =91it' was not declared in this scope

where 'line 42' refers to the line with the iterator declaration.
Can somebody explain to me what I do wrong?

Tanks in advance.
Bertwim


Another hint (the typename thing is already explained well): leading
underscores are reserved for compiler usage. E. g. Andrei Alexandrescu
prefers trailing underscores for members. I would recommend this, too.
Or use the MS style "m_" prefix... ;-)

br
Juergen

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