Re: std::map insert element issue

From:
i.albert.cheng@gmail.com
Newsgroups:
comp.lang.c++
Date:
Thu, 5 Feb 2009 03:33:17 -0800 (PST)
Message-ID:
<db108915-6f11-4cd4-94a1-c760edffacec@k36g2000pri.googlegroups.com>
On Feb 5, 5:51 am, zs0723 <zs0...@gmail.com> wrote:

I need to changed the value of a key in std::map, i have written the
following code :

#include <map>
#include <iostream>
#include <string>
using namespace std;

int main()
{
   typedef map<string,string> TABLE;
   typedef TABLE::iterator ITERATOR;
   TABLE table;

   table.insert(TABLE::value_type("zs","victor"));

   if(table.insert(TABLE::value_typezs","xiao v")).second) // this
will failed , i can't overwirte the exist key's value
      cout<<"insert success\n";
   else
      cout<<"insert failied\n";

// but use like array 's [] , it's ok
// table["zs"]="victor";
// table["zs"]="xiao v";
   for(ITERATOR itr=table.begin();itr != table.end() ; ++itr)
   {
         cout<<itr->first <<":"<<itr->second;
         cout<<endl;
   }

   cout<<std::endl;

}

My question is :
   Why insert method can't overwrite the value of the existing key=

..

Thanks


Basically there two ways of inserting item in terms of std::map.

1>
The first and more traditional way is call insert() which applies to
all unique associative containers , e.g std::set , std::map.
When doing a a.insert(t),inserts t into a if and only if a does not
already contain an element whose key is the same as the key of t.

2>
The second way is unique for std::map , called operator[], which is
only for convenience, not necessary needed.
It merely equals to (*(a.insert(t, data_type()).first)).second .

Gob00st

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