Re: index of std::vector with condition

From:
Stuart Golodetz <sgolodetz@NdOiSaPlA.pMiPpLeExA.ScEom>
Newsgroups:
comp.lang.c++
Date:
Tue, 13 Jul 2010 02:52:23 +0100
Message-ID:
<RdCdnUdMrctFW6bRnZ2dnUVZ8lmdnZ2d@pipex.net>
Alf P. Steinbach /Usenet wrote:

* Stuart Golodetz, on 13.07.2010 01:53:

Philipp Kraus wrote:

Hello,

is there a fast way to create a index with condition of a std::vector?

For illustrating:

I have a vector mydata with some data and I would like to create a
vector with unique elements

std::vector<T> l_unique( mydata );

std::sort( l_unique.begin(), l_unique.end() );

l_unique.erase( std::unique( l_unique.begin(), l_unique.end()),
l_unique.end() );

in the next step I will do this

std::vector< std::vector<std::size:t> > index;

for(std::size_t i=0; i < l_unique.size(); ++i) {

      std::vector<std::size_t> y;

      for(std::size_t n=0; n < mydata.size(); ++n)

if (mydata[n] == l_unique[i])

y.push_back(n);

index.push_back(y);

}

Can I do this two for loops more efficient? I would like to get the
index position in my data vector from a unique set of the elements
within the vector.

Thanks for help

Phil


Anything wrong with this sort of approach?

int arr[] = {3,2,2,3,3,1,1,5,6};
std::vector<int> v(&arr[0], &arr[sizeof(arr)/sizeof(int)]);

std::map<int,std::vector<size_t> > index;
for(size_t i=0, size=v.size(); i<size; ++i)
{
     index[v[i]].push_back(i);
}


Yes, it accesses non-existing elements of 'index'.

One reasonable way to build an index is as follows:

<code>
#include <iostream>
#include <map>
#include <algorithm>
#include <stddef.h>

typedef ptrdiff_t Size;
typedef ptrdiff_t Index;

template< class Type, Size n >
Size size( Type (&)[n] ) { return n; }

int main()
{
    typedef std::multimap< int, Index > Map;
    typedef Map::value_type MapValue;
    typedef Map::iterator MapIter;

    int const arr[] = { 3,2,2,3,3,1,1,5,6 };

    Map map;
    for( Index i = 0; i < size( arr ); ++i )
    {
        map.insert( MapValue( arr[i], i ) );
    }

    for( MapIter it = map.begin(); it != map.end(); ++it )
    {
        std::cout << it->first << " -> " << it->second << std::endl;
    }

    std::cout << std::endl;
    std::cout << "All occurrences of 3:" << std::endl;
    for( MapIter it = map.lower_bound( 3 ); it != map.upper_bound( 3 );
++it )
    {
        std::cout << it->second << " ";
    }
    std::cout << std::endl;
}
</code>

The general idea is sorting the original data set. In the code above the
sorting is done externally by insertion into a tree (inside 'map').
Alternatively it can be done in-place by applying e.g. std::sort.

Cheers & hth.,

- Alf


On a separate note, I'm happy to defer to your greater wisdom on this in
general, but you do realise you're recalculating map.upper_bound(3) on
each iteration of the loop, right? :)

Stu

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