Re: index of std::vector with condition

From:
Stuart Golodetz <sgolodetz@NdOiSaPlA.pMiPpLeExA.ScEom>
Newsgroups:
comp.lang.c++
Date:
Tue, 13 Jul 2010 10:17:42 +0100
Message-ID:
<IvydnQ687_CqsqHRnZ2dnUVZ7sKdnZ2d@pipex.net>
Alf P. Steinbach /Usenet wrote:

* Stuart Golodetz, on 13.07.2010 03:52:

Alf P. Steinbach /Usenet wrote:

* Stuart Golodetz, on 13.07.2010 01:53:

Philipp Kraus wrote:

Hello,

is there a fast way to create a index with condition of a std::vector?

For illustrating:

I have a vector mydata with some data and I would like to create a
vector with unique elements

std::vector<T> l_unique( mydata );

std::sort( l_unique.begin(), l_unique.end() );

l_unique.erase( std::unique( l_unique.begin(), l_unique.end()),
l_unique.end() );

in the next step I will do this

std::vector< std::vector<std::size:t> > index;

for(std::size_t i=0; i < l_unique.size(); ++i) {

std::vector<std::size_t> y;

for(std::size_t n=0; n < mydata.size(); ++n)

if (mydata[n] == l_unique[i])

y.push_back(n);

index.push_back(y);

}

Can I do this two for loops more efficient? I would like to get the
index position in my data vector from a unique set of the elements
within the vector.

Thanks for help

Phil


Anything wrong with this sort of approach?

int arr[] = {3,2,2,3,3,1,1,5,6};
std::vector<int> v(&arr[0], &arr[sizeof(arr)/sizeof(int)]);

std::map<int,std::vector<size_t> > index;
for(size_t i=0, size=v.size(); i<size; ++i)
{
index[v[i]].push_back(i);
}


Yes, it accesses non-existing elements of 'index'.

One reasonable way to build an index is as follows:

<code>
#include <iostream>
#include <map>
#include <algorithm>
#include <stddef.h>

typedef ptrdiff_t Size;
typedef ptrdiff_t Index;

template< class Type, Size n >
Size size( Type (&)[n] ) { return n; }

int main()
{
typedef std::multimap< int, Index > Map;
typedef Map::value_type MapValue;
typedef Map::iterator MapIter;

int const arr[] = { 3,2,2,3,3,1,1,5,6 };

Map map;
for( Index i = 0; i < size( arr ); ++i )
{
map.insert( MapValue( arr[i], i ) );
}

for( MapIter it = map.begin(); it != map.end(); ++it )
{
std::cout << it->first << " -> " << it->second << std::endl;
}

std::cout << std::endl;
std::cout << "All occurrences of 3:" << std::endl;
for( MapIter it = map.lower_bound( 3 ); it != map.upper_bound( 3 );
++it )
{
std::cout << it->second << " ";
}
std::cout << std::endl;
}
</code>

The general idea is sorting the original data set. In the code above
the sorting is done externally by insertion into a tree (inside
'map'). Alternatively it can be done in-place by applying e.g.
std::sort.

Cheers & hth.,

- Alf


On a separate note, I'm happy to defer to your greater wisdom on this in
general, but you do realise you're recalculating map.upper_bound(3) on
each iteration of the loop, right? :)


Not so great wisdom in my old senile head...

I thought you were using a std::vector, not a std::map; sorry, cross-eyed.

And yes, above code is needlessly inefficient.

Grumble...

Happily, one thing I've learned is that even the best make errors and do
silly things, and when they can, then who am I to feel down about a few
misstakes?

Cheers, & thanks,

- Alf


No worries - you've corrected enough of them in the past to know that
I've made more than my fair share of errors :) I did wonder whether the
multimap approach was more appropriate actually when writing my original
post. I think it possibly depends on the specifics of how the index is
being used, which we weren't told.

Cheers,
Stu

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