Re: Returning map from map of maps without any copy

From:
Ian Collins <ian-news@hotmail.com>
Newsgroups:
comp.lang.c++
Date:
Sat, 03 Dec 2011 20:36:50 +1300
Message-ID:
<9ju1sjF570U3@mid.individual.net>
On 12/ 3/11 08:08 PM, ittium wrote:

Group,
I have a class that contains (STL) map of maps. This Class has a getMap
function that return one map out of the map of maps. I need to avoid
copies while extracting the map. There are two approaches
1. I pass a "map" reference in getMap function, the getMap method
extract appropriate map and put it in the passed map reference. It seems
copy will be made while doing
    map=Extracted Map; //map is reference parameter in getMap function

2. Second option is to return a reference from the getMap function
(please ignore dangling pointer issue since this class is likely to live
forever). My doubt is
    - Can I return a iterator->second as reference
    - If I can return it, how can caller save it (without making a copy).

Please note that maps to be returned are big and copying them is going
to be a big overhead.'

Is there a better solution to handle this.


One way is to return a proxy object to a map. Some like this:

#include <iostream>
#include <map>

typedef std::map<int,int> Inner;
typedef std::map<int,Inner> Outer;

struct Container
{
   Outer map;

   struct OuterProxy
   {
     const int index;
     Outer& mine;

     OuterProxy( Outer& outer, int n ) : mine(outer), index(n) {}

     int operator[]( int n ) { return mine[index][n]; }
   };

   OuterProxy operator[]( int n ) { return OuterProxy( map, n ); }
};

int main( int argc, char** argv )
{
   Container container;

   Inner inner;

   inner[42] = 21;

   container.map[2] = inner;

   std::cout << container[2][42] << std::endl;

   return 0;
}

--
Ian Collins

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