Re: Anonymous union rules against constructors & assignment

From:
"Bo Persson" <bop@gmb.dk>
Newsgroups:
comp.std.c++
Date:
Wed, 7 Jun 2006 10:39:30 CST
Message-ID:
<4eo9kjF1f86otU1@individual.net>
""Crosbie Fitch"" <crosbie@digitalproductions.co.uk> skrev i
meddelandet news:nrGdndeyd-B6ORvZnZ2dnUVZ8s6dnZ2d@bt.com...

<johnchx2@yahoo.com> wrote in message
news:1149633364.561734.56320@i39g2000cwa.googlegroups.com...

memcpy doesn't work on non-PODs.
This is because they aren't guaranteed to be laid out anything like
you
think they will be.


'memcpy doesn't work on non-PODs' !!!

Wow! That's bad news.


How would it work?!

Try this one:

class nonPOD
{
public:
    nonPOD() : ref(&y)
    { }

    int gety() const
    { return ref; }

private:
   int y;
   int& ref;

   nonPOD(const nonPOD&);
   nonPOD& operator=(const nonPOD&);
};

This class can be constructed, but it cannot be copied or assigned
(because the copy constructor and assignment operator are private).

Do you think it would be a good idea to allow memcpy to make copies?
How would the gety() function work if the class object is
moved/copied?

So, let's say I had this:

class A {... }* a;

foo()
{void* p=malloc(sizeof(A));

new(p) A();

a=(A*)malloc(sizeof(A));

memcpy(a,p,sizeof(A)); // Doesn't work if A is non-POD?


No. What if class A contains a pointer to some other data. Will that
data be deleted once, twice, or not at all?

free(p);

a->method();

delete a;
}

That's all. It's such a weeny little thing.


No, it's not. It is a fundamental change!

Bo Persson

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