overriding some of the methods with the same name yields an error

From:
"Oren" <oren.pub@gmail.com>
Newsgroups:
comp.std.c++
Date:
Thu, 8 Jun 2006 08:26:06 CST
Message-ID:
<1149764160.967774.160560@j55g2000cwa.googlegroups.com>
Hi
There is a question I'm trying to solve for some time without any
success:
When a base class has several methods with the same name (overloaded)
and a derived class overrides one or some of the methods all other (not
overridden) methods are hidden as well.
for example:

#include <iostream>
using namespace std;

class B
{
public:
    virtual void foo(const char* arg)
    {cout<<"B::foo(const char*):"<<arg<<endl;}

    virtual void foo(int arg)
    {cout<<"B::foo(int):"<<arg<<endl;}
};

class D :public B
{
public:
    virtual void foo(int arg)
    {cout<<"D::foo(int):"<<arg<<endl;}
};

int main()
{
    D* d = new D();
    d->foo("hello");
    d->foo(3);
    delete d;
    return 0;
}

this example refuses to compile on account of the "hello" char[6] not
able to be converted to an int. I tried it on g++ and VC6 and both did
the same so I guess it's not a compiler bug but rather a standard rule
or direction.
BTW when d's type is replaced to a B* the program runs OK.
my question is why am I seeing this behavior and what is the logic
behind this?

Thanks
Oren

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