Re: this

"Priya Mishra" <mis.priya@gmail.com> wrote in message
news:1151473208.211188.69380@j72g2000cwa.googlegroups.com...


this simply points to the instance of the object that the method is being
called on. Usually it is not needed. Sometimes it is (such as to return a
pointer to itself). An example may illistrate.

#include <iostream>
#include <string>

class MyClass
{
public:
   MyClass* GivePointer() { return this; }
};

void main()
{
   MyClass* MyInstance = new MyClass();

   MyClass* ObjectPointer = MyInstance->GivePointer();

   if ( MyInstance == ObjectPointer )
      std::cout << "Equal Pointers" << std::endl;
   else
      std::cout << "Not Equal Pointers" << std::endl;

   std::string wait;
   std::cin >> wait;
}

The output of this is:
Equal Pointers.

Again, usually you do not need to know the pointer of the instance you are
calling a method on. Sometimes you do though. If you don't need it, don't
worry about it.