Re: doubt on scope of pointers VERY URGENT!!!!!!!!! PLEASE HELP ME.........
Yes, the objects are kept in the vector. The scope of *ptr* is the
function *init()*, but after *push_back()* is called, the value of
pointer is COPIED and it is kept in the vector. The scope of the vector
is determined by the lifecycle of the instance of class A. When A's
constructor is called, the vector is established; and when A's
destructor is called, the vector is destoried.
edu.mvk wrote:
Hi ,
if the program is like this ...
please tell me the scope of the "ptr" and the vector "vec_ptr"...
class A
{
private :
vector< B* > vec_ptf ;
public :
init();
shutdown();
}
A :: init()
{
B *ptr;
int i=0;
while( i < 10 )
{
ptr = new B();
vec_ptr.push_back( ptr );
}
}
A :: shutdown()
{
if ( !vec_ptr.empty() )
{
vector<B*>::iterator B_Iterator;
for( B_Iterator = vec_ptr.begin(); B_Iterator !=
vec_ptr.end(); B_Iterator++ )
{
delete( vec_ptr[QCop_Iterator] );
}
}
}
if i have declared and instantiated the " ptr " in the function init()
like above and after pushing that into the vector of type B* will the
object be remain even in the shutdown() function....??
please tell me the scope of that pointer ptr and the vector that
containing the ptr.
Tthanks
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