Re: Initializing without assigning

From:

"Calle Pettersson" <CPettsson@gmail.com>

Newsgroups:

comp.lang.c++

Date:

19 Jul 2006 13:22:36 -0700

Message-ID:

<1153340556.695525.242430@m79g2000cwm.googlegroups.com>

Roland Pibinger wrote:

On Wed, 19 Jul 2006 12:11:14 -0400, "Victor Bazarov"
<v.Abazarov@comAcast.net> wrote:

Pete Becker wrote:

Calle Pettersson wrote:

Coming from writing mostly in Java, I have trouble understanding how
to declare a member without initializing it, and do that later... In
Java, I would write something like
public static void main(String[] args) {
MyType aMember;
...
aMember = new MyType(...)
...
}

The roughly equivalent C++ code would be

MyType *aMember = 0;
...
aMember = new MyType(...);

To the OP:

If 'aMember' is a local variable of the 'main' function ("method"), then
its name is wrong. It's not really a member, is it?

Correct, I came up with that method just to show my point, and did so
in an erronus way, which understandably caused some confusion... I'll
try to be more careful in reading my code before posting in the future.

Moreover, uninitialized variables are nor allowed in Java.

Yes they are, as long as you don't try to access them. This will work
just fine:
class MyClass {
public static void main(String[] args) {
  MyObject obj;
  // blahblahblah
  obj = new MyObject();
  // etc
}
}