Overloading operator delete problem

From:
"albrecht.fritzsche" <albrecht.fritzsche@arcor.de>
Newsgroups:
comp.lang.c++.moderated
Date:
26 Aug 2006 12:40:46 -0400
Message-ID:
<44f075b8$0$1401$9b4e6d93@newsspool3.arcor-online.net>
Hi,

I've overloaded operator new and operator delete like in the appended
code but don't know how to trigger a call to the nothrow-delete.
While the call to the nothrow-new is easy by specifying

     int* p = new(nothrow) int;

how do I call the nothrow-delete

     delete (nothrow) p;

does not work.

At least on Vis C++ the appended code compiles but uses for the last
delete the throwing-delete version. How do I have to specify the
std::nothrow? Where is this actually documented in the standard?

And, why do I get a strange error from Comeau (online) with exactly
this code saying

"ComeauTest.c", line 6: error: exception specification is incompatible with that of
          previous function "operator delete(void *)" (declared at line 67 of
          "new.stdh"):
            previously specified: no exceptions will be thrown
  void operator delete(void* memory) throw(std::bad_alloc) {
                                     ^


Thanks for any help finding what I am doing wrong
Ali

#include <new>
#include <cstdlib>
void* operator new(size_t count) throw (std::bad_alloc) {
     return malloc(count);
}
void operator delete(void* memory) throw(std::bad_alloc) {
     free(memory);
}

void* operator new(size_t count, const std::nothrow_t&) throw () {
     return malloc(count);
}
void operator delete(void* memory, const std::nothrow_t&) throw() {
     free(memory);
}

int main() {
     int* i = new int();
     int* j = new(std::nothrow) int();

     delete i;
     delete /*(std::nothrow)*/ j; // how to specify the nothrow?

     return 0;
}

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