Re: why dynamic_cast fail here?

From:
pietromas@gmail.com
Newsgroups:
comp.lang.c++
Date:
15 Mar 2007 05:21:12 -0700
Message-ID:
<1173961272.505732.213100@l75g2000hse.googlegroups.com>
On Mar 15, 12:12 pm, Rolf Magnus <ramag...@t-online.de> wrote:

pietro...@gmail.com wrote:

In the example below, why does the dynamic_cast fail (return NULL)?


Because a B is not a C.

It should be able to cast between sibling classes ...


No, it shouldn't. An instance of class B only provides the A interface and
the B interface. So why would you want to access it through the C
interface? What would you expect to happen if C had another member function
and you'd try to call that on your B?

#include <iostream>

class A
{
    public:
        virtual const int get() const = 0;
};

class B : public A
{
    public:
        virtual const int get() const { return 0; }
};

class C : public A
{
    public:
        virtual const int get() const { return 1; }
};

int main()
{
    A *a;

    a = new B();
    std::cout << a->get() << std::endl;

    a = dynamic_cast<C*>(a);
    if(a)
        std::cout << a->get() << std::endl;

    return 0;
}


Yes, I see how that could case problems. So does that mean that the
following is not true (http://www.acm.org/crossroads/xrds3-1/
ovp3-1.html):

"The dynamic_cast Operator

The dynamic_cast operator takes the form

   dynamic_cast<T> (expr)

and can be used only for pointer or reference types to navigate a
class hierarchy. The dynamic_cast operator can be used to cast from a
derived class pointer to a base class pointer, cast a derived class
pointer to another derived (sibling) class pointer, or cast a base
class pointer to a derived class pointer. Each of these conversions
may also be applied to references. In addition, any pointer may also
be cast to a void*."

Or else, what are the conditions for casting between sibling classes?

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