Re: Deleting an Object and setting the Pointer to NULL

From:
"James Kanze" <james.kanze@gmail.com>
Newsgroups:
comp.lang.c++.moderated
Date:
Sun, 18 Mar 2007 14:34:30 CST
Message-ID:
<1174213457.050914.312520@o5g2000hsb.googlegroups.com>
On Mar 17, 9:50 pm, Seungbeom Kim <musip...@bawi.org> wrote:

James Kanze wrote:

There are several very important reasons:

  -- Finally, most of the time when there is just a single
     pointer, it is in an object, and the delete is in the
     destructor, so there's no point---the pointer itself will
     cease to exist.


Except when the pointer is in a container, in which case you have to
explicitly set the pointer to null to avoid undefined behaviour,


In theory. (But of course, then it's not a case of "just a
single pointer", either.) In practice, it's not something I
worry about in production code.

And of course, the other solution would be to remove it first
from the container. Something like:

     while ( ! myVector.empty() ) {
         T* p = myVector.back() ;
         myVector.pop_back() ;
         delete p ;
     }

More "in", of course, would be to use swap:

     for ( std::vector< T >::iterator iter = myVector.begin() ;
             iter != myVector.end() ;
             ++ iter ) {
         T* p = NULL ;
         std::swap( p, *iter ) ;
         delete p ;
     }

(I'm just joking, of course. See below for a more reasonable
solution.)

IIRC:

     for (i = begin(); i != end(); ++i) delete *i, *i = 0;
or
     for (i = begin(); i != end(); ++i) delete i->second, i->second = 0;


Formally, I think that even those have undefined behavior. You
have to remove the pointer from the container in some way
(removing the element or changing its value) *before* the
delete. The simple presence of the pointer in the container
after delete is undefined behavior, and presumable, the
operator*() called in the expression to null the pointer could
in fact trigger such undefined behavior.

In the past I've written the following to avoid repeating the same code:

template <typename T>
inline void delete_ptr(const T*& p)
{ boost::checked_delete(p); p = 0; }


If you really care:

     {
         T* tmp = p ;
         p = NULL ;
         delete tmp ;
     }

Otherwise, you've not eliminated the undefined behavior.

Note, however, that you're still not setting to null the operand
of the delete:-).

--
James Kanze (Gabi Software) email: james.kanze@gmail.com
Conseils en informatique orient?e objet/
                    Beratung in objektorientierter Datenverarbeitung
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