Re: Call constructor in another
On Apr 29, 10:02 am, terminator <farid.mehr...@gmail.com> wrote:
On Apr 28, 8:58 am, Blair Craft <lai...@square-enix.net.cn> wrote:
hi,
I got a class have 2 constructors:
static int g_idx_counter = 0;
[code]
Object::Object():{
counter = g_idx_counter++;
created_at = last_used = time(NULL);
destroyed = false;
id = -1;
}
Object::Object(int _id){
Object();
id = _id;}
[/code]
when I use:
Object *o = new Object();
everything is OK, but when using the second constructor:
Object *o = new Object(32);
member variable "counter" will remain untouched, I did a gdb trace,
Object::Object() was invoked and inside that function "counter" was
initialized, when function returns "counter" went back to 0
again. Behavior is like a local variable inside a code chunk, but here
counter is a class member variable, anyone can shed some light?
thanks
put shared instructions in a member function and call it in both
ctors:
void Object::build(){
counter = g_idx_counter++;
created_at = last_used = time(NULL);
destroyed = false;
id = -1;
};
Object::Object(){
build();
};
Object::Object(const Object& ob){
build();
id=ob.id;
};
A private initializer member function is a good solution. The above
ctor is a copy ctor.
so calling the initializer function here
Object::Object(int _id){
build();
id = _id;
}
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