On Apr 30, 6:17 pm, aki <akhileshrawat...@gmail.com> wrote:
i am writing codes for implementing network protocols.
i have written a method which is receiving a packet from network.
i have assumed that the packet i will receive will be of type char*.
i need to test my method and
for that i want to create a network buffer which will contain a
packet of format as->
example of Configuration req packet
uint8_t code;
uint8_t identifier;
uint16_t length;
option1
option2
.....
option n
for eg option1 can be.... AuthProtocol with fields as
uint8_t type;
uint8_t length;
uint16_t authpro;
i was tryin to do like this.. but it has a limitation....
supposing packet contains header and only one option..
it will need 8 byte aas a whole..
char *buffer=new char(8);// allocating buffer with required memory
No. Here, you've allocated a single char, and initialized it
with the value 8. what you probably want is:
std::vector< char > buffer( 8 ) ;
Although for various reasons, I find it easier to work with an
std::vector< unsigned char > for this sort of thing (unless the
protocol is text based).
If you're generating a buffer for output, just declaring:
std::vector< unsigned char > buffer ;
and using push_back to insert the values is generally
sufficient. In this case, something like:
buffer.push_back( code ) ;
buffer.push_back( identifier ) ;
size_t lengthOffset - buffer.size() ;
buffer.push_back( 0 ) ; // Save space for length...
buffer.push_back( 0 ) ;
insertOptions( buffer ) ;
assert( buffer.size() < 1 << 16 ) ;
buffer[ lengthOffset ] = buffer.size() >> 8 ;
buffer[ lengthOffset + 1 ] = buffer.size() ;
(This assumes Internet format for unsigned integers.)
memset(buffer,1,1); // setting code field as 1
You don't need memset to set a single byte.
memset(buffer+1,4,1); // setting identifier as 4
memset(buffer+2,25,2); // here i am not able to put length in 2 byte
field as memset works with only one byte ...
Memset cannot be used for anything other than a stream of bytes.
Forget it (and memcpy) for generating buffers for protocols.
Just use a vector< unsigned char >, as above, then, to pass it
to the socket interface:
reintepret_cast< char* >( &buffer[ 0 ] ) ;
(Generally, reintepret_cast's are not a very good idea, but this
is the exception which confirms the rule.)
--
James Kanze (Gabi Software) email: james.ka...@gmail.com
Conseils en informatique orient=E9e objet/
Beratung in objektorientierter Datenverarbeitung
9 place S=E9mard, 78210 St.-Cyr-l'=C9cole, France, +33 (0)1 30 23 00 34
well i am a newbie in this field... but i was unable to do by the
i tried with this way ....
char *buffer=new char(8); // it workin.like this...
output is like this..